eular project-problem6

PROBLEM 6
The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025  385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

ANSWER


25164150

JAVA CODE


public class Problem6 {
public static void main(String[]args){
int sumOfTheSquares=0;
int squareOfTheSum=0;
for (int i = 0; i <101; i++) {
sumOfTheSquares+=(int)Math.pow(i, 2);
squareOfTheSum+=i;
}
System.out.println((int)Math.pow(squareOfTheSum,2)-sumOfTheSquares);
}
}